cos x =0 or tan x =-1
HOW
2006-09-16 06:17:59 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do you mean
3(sin(2x) + 2cos(x)^2) + 3(1 - sin(2x) + 2sin(x)) = 28
3((sin(2x) + 2cos(x)^2) + (1 - sin(2x) + 2sin(x)) = 28
sin(2x) + 2cos(x)^2 + 1 - sin(2x) + 2sin(x) = 7
(1 - 1)sin(2x) + 2cos(x)^2 + 1 + 2sin(x) = 7
2cos(x)^2 + 1 + 2sin(x) = 7
2(1 - sin(x)^2) + 1 + 2sin(x) = 7
2 - 2sin(x)^2 + 1 + 2sin(x) = 7
-2sin(x)^2 + 2sin(x) + 3 = 7
-2sin(x)^2 + 2sin(x) - 4 = 0
-2(sin(x)^2 - sin(x) + 2) = 0
sin(x)^2 - sin(x) + 2 = 0
if you do mean the above, then this problem will give you complex values.
2006-09-16 12:12:49 · answer #1 · answered by Sherman81 6 · 0⤊ 1⤋
You would have to satisfy BOTH
3^3 + 3^0 = 28
Where the first term equals 3 AND the second term equals 0.
2006-09-16 09:08:38 · answer #2 · answered by Anonymous · 0⤊ 1⤋
That is incorrect SYNTAX ERROR
2006-09-16 06:32:06 · answer #3 · answered by Mimi 3 · 0⤊ 1⤋