I need to cancel something out in this expression:
(x-sin (2x))/(sin x)
How do I do it?
2006-09-16 04:58:01 · 6 answers · asked by ttizzle999 3 in Science & Mathematics ➔ Mathematics
(x - sin(2x))/(sin(x)
(x - (2sinx * cosx))/(sin(x))
(x - 2sinxcosx)/(sin(x))
(x/(sin(x)) - (2sinxcosx/sinx)
(x/sin(x)) - 2cos(x)
(x * sin(x)^-1) - 2cos(x)
(x * csc(x)) - 2cos(x)
ANS : x*csc(x) - 2cos(x)
2006-09-16 12:21:27 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
x - sin 2x / sin x
= x - 2sin x * cos x / sin x
= (x / sin x) - 2*cos x
2006-09-16 12:31:52 · answer #2 · answered by عبد الله (ドラゴン) 5 · 0⤊ 1⤋
That's all you can do:
x/SIN(x) - 2·COS(x)
2006-09-16 12:05:57 · answer #3 · answered by linen 2 · 0⤊ 1⤋
take this hint : sin 2x= 2 sin x cosx ,so
(x-sin2x)/sinx=(x-2sinxcosx)/sinx=(x/sinx)-2cosx
2006-09-16 12:08:32 · answer #4 · answered by Mr.Integral 2 · 0⤊ 1⤋
I don't think there is a good simplification of this expression.
2006-09-16 12:01:08 · answer #5 · answered by bruinfan 7 · 0⤊ 1⤋
Try cancelling your brain. Oh, I'm sorry - you've already done it.
2006-09-16 12:03:46 · answer #6 · answered by Anonymous · 0⤊ 1⤋