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If A is travelling at 72 km per hour on a highway. B is travelling at a speed of 25 meters per second on a highway. What is the difference in their speeds in m/sec.

2006-09-15 19:26:24 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

Take the speed in km / hour and convert it to m/sec:

A is going:
72 km / hour * 1000 m / km * 1 hr / 3600 minutes
72000 / 3600 = 20 m / sec

B is going:
25 m / sec

The difference is 25 - 20 = 5 m / sec

B is travelling 5 m/sec faster than A.

2006-09-15 19:31:31 · answer #1 · answered by Puzzling 7 · 0 0

72 km/hr = 72 * 5/18 m/s = 20 m/s

diff = 25 m/s -20 m/s = 5 m/s


( you get 5/18 as 1 km = 1000 m and 1 hr = 60*60 sec )

2006-09-15 21:02:00 · answer #2 · answered by Anonymous · 0 0

You need to convert it so that both are traveling the same, what I mean is, you have 72 km an hour and 25 meters, do you mean km as well? also convert both to per hour or to second and go from there.

2006-09-15 19:34:32 · answer #3 · answered by Sandi A 4 · 0 0

A's speed=72*5/18=20 m/s
B's speed=25 m/s
difference=5 m/s

2006-09-15 19:32:21 · answer #4 · answered by raj 7 · 0 0

72 KM/hour = 72,000 M/hour / 3600 (number of seconds in an hour) = 20 M/Sec., 5 m./second slower then the other fellow.

2006-09-15 19:36:08 · answer #5 · answered by PtolemyJones 3 · 0 0

5 meters per second
72000metersper hour diveded by 3600 seconds= 20 meters per second
25 - 20=5

2006-09-15 19:31:27 · answer #6 · answered by sllyjo 5 · 0 0

72 kmph = 72000/3600 mps => 20 mtrs / sec
the diff is 25 - 20 mtr / sec => 5 mtr / sec

2006-09-15 19:40:44 · answer #7 · answered by rags 2 · 0 0

72km/h = 20m/sec

Thus Diff = 25-20 = 5 m/sec

2006-09-15 19:32:22 · answer #8 · answered by ctyuang 1 · 0 0

72 km/h = 72000/3600 m/s
=20m/s.

Therefore, difference in their speeds in m/s = 5m/s

2006-09-16 03:33:08 · answer #9 · answered by noesis 2 · 0 0

72 km/h=72000(m)/60(minute)*60(seconds)=72000/3600 m/s=20 m/s
so it is 5 m/s less that other one

2006-09-15 19:53:13 · answer #10 · answered by F M 1 · 0 0

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