How do you solve B=3/4(A-10), for A?
Thanks.
Also, by the way, don't just give me the answer. Can you tell me how to work it out?
2006-09-15 18:24:29 · 7 answers · asked by CaliGurl♥ 6 in Science & Mathematics ➔ Mathematics
multiply each side by 4/3
4/3B=A-10
add 10 to each side
A=4/3B+10
2006-09-15 18:28:11 · answer #1 · answered by Some Kid 2 · 1⤊ 0⤋
You didn't write the equation in an unambiguous form!
If B = (3/4)*(A-10) then first multiply both sides by 4/3 then add 10 to each side.
If B = 3/(4*(A-10)) then multiply each side by (A-10), divide by B then add 10 to each side
2006-09-16 01:33:31 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
B=3/4(A-10)
4/3B=(4/3)(3/4)(A-10)
4/3B=A-10
4/3B+10=A-10+10
4/3B+10=A
what u do to one side you must do to the other.here you are trying to isolate A
2006-09-16 01:50:45 · answer #3 · answered by cee 2 · 0⤊ 0⤋
Multiply b/s of eq. by reciprocal of 3/4 , we get
4/3B = 4/3*3/4(A-10)
then we have
4/3B = A-10
Now add 10 on B/S
4/3B + 10 = A-10+10
Wwe get
4/3B+10 = A
or
A = 4/3B+10
Clear
Best of luck
2006-09-16 01:34:20 · answer #4 · answered by shani s 1 · 0⤊ 0⤋
Solve using the change of formula.b=3a-30/4,4b=3a-30,3a=4b+30,a=4b+30/3.therefore the answer is a=3b+30/4
2006-09-16 01:29:50 · answer #5 · answered by SABHA A 2 · 0⤊ 0⤋
multiply each side by 4/3
4/3B=A-10
add 10 to each side
A=4/3B+10
2006-09-16 01:31:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋
multiplying by 4/3, we get
4b/3=a-10
a=4b/3+10
a=(4b+30)/3
2006-09-16 01:30:25 · answer #7 · answered by SkkARd 3 · 0⤊ 0⤋