I think you're thinking of equivalence relations, and not "equality." For equality, it is an axiom in mathematics that if x=y and y=z then x=z. However, if you defined a relation ~ on the set of invertible 2x2 matrices with complex coefficients by saying that A~B if A and B share a common eigenvalue, then it would be very possible for A~B and B~C but A not equivalent to C (take A to be the diagonal matrix with 1 and 2 on the diagonal, B diagonal with 2 and 3 on the diagonal, and C be diagonal with 3 and 4 on the diagonal; then A and B share 2, B and C share 3, but A and C share nothing).
That's the closest to getting the claim you're making. Otherwise, it's just not right.
2006-09-15 18:57:44
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answer #1
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answered by wlfgngpck 4
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You have used equal, not congruent so it is possible that there are some differences between the y that equals x and the y that equals z making x not necessarily equal to z. This is probably your work assignment and so you need to prove it, the rest of us don't really care unless we are bored enough to want to put in the required level of skull sweat. I'm on overtime and so out of here.
2006-09-15 15:19:25
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answer #2
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answered by St N 7
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nope - x=z, and there's not a way to prove it doesn't necessarily equal z.
2006-09-15 15:08:02
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answer #3
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answered by a_blue_grey_mist 7
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(x + y)(x - z) = x^2 - xz + xy - yz The "formula" is the distributive assets of algebra. right here is the way it works: X*X then X*-Z then Y*X then Y*-Z Take the 1st fee from the left section, multiply it with the 1st fee from the subsequent set of parenthesis (X*X). next, take the 1st fee from the left section and multiply it with the 2nd fee from the 2nd set of parenthesis. proceed working for the time of the subject. puzzled with the help of all the words? Watch how the 2nd equation is labored. (x + y + z)(x + y + z) x^2 + xy + xz + yx + y^2 + yz + zx + zy + z^2 Rearrange words x^2 + xy + xz + xy + y^2 + yz + xz + yz + z^2 (place in alphabetical order) combine words x^2 + 2xy +2xz + y^2 + yz + z^2 (x + y + z)(x + y + z) = x^2 + 2xy +2xz + y^2 + yz + z^2
2016-12-18 11:03:20
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answer #4
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answered by Anonymous
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mathematically you cant prove that x is not equal to z
2006-09-15 15:27:58
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answer #5
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answered by A 3
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x = you eat too much
y = you are fat
z = you can't walk fast
There...This proves it....and as you said x is not necessarily equal to z.
2006-09-15 15:11:16
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answer #6
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answered by knowbuddycares 3
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I think it is impossible that x does not equal z, but please do prove me wrong.
2006-09-15 15:12:51
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answer #7
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answered by Jack Spam 2
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Your point besides that you can ask irrelevant questions?
2006-09-15 15:13:30
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answer #8
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answered by Nelson_DeVon 7
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I am not sure how you would do that and not violate any math laws.
2006-09-15 15:17:30
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answer #9
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answered by zahbudar 6
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x=z . Any so-called proof you have is faulty.
2006-09-15 15:13:31
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answer #10
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answered by banjuja58 4
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