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The perimter of a rectangle is 40cm. The width is 8cm less than the length. Find the width and the length.

PLease help..i think i might have the right answer Lengthis 14..width is 6

2006-09-15 13:24:36 · 13 answers · asked by stahl7639 2 in Science & Mathematics Mathematics

13 answers

well, lets start by assigning a variable to the unknown

length=L

the width then, (because it is 8 less than the length) is L-8

the perimeter is the distance all the way around which means two lengths and two widths so

L+L+(L-8)+(L-8)=40

4L-16=40
4L=56
L=14

and, width is 8 less than 14, and is 6

looks like you got it right

good job

keep at it
math is power

2006-09-15 13:29:35 · answer #1 · answered by enginerd 6 · 0 0

You're Absolutely Right.

Here is how:

VERIFICATION:

Perimeter of a Rectangle = 2 (l+ b)
= 2 ( 14 + 6)
= 2 8 20
= 40 cm. QED

2006-09-15 20:33:29 · answer #2 · answered by Anonymous · 0 0

Yes, you have the right answer!

The perimeter is 2*length + 2*width.
Therefore, length + width = 20
And you know length = width + 8

Therefore, (width + 8) + width = 20
So 2*width = 12
and width = 6
... and since length = width + 8, it follows that length = 14.

2006-09-15 20:27:26 · answer #3 · answered by Bramblyspam 7 · 0 0

P = 2(L + W)
40 = 2(L + W)
20 = L + W

W = L - 8

20 = L + (L - 8)
20 = L + L - 8
20 = 2L - 8
2L = 28
L = 14

W = 14 - 8 = 6

Length = 14cm
Width = 6cm

2006-09-15 20:44:54 · answer #4 · answered by Sherman81 6 · 0 0

width = ( X-8 ) length = X

2X + 2(X - 8) = 40
2X + 2X -16 =40
4X - 16 =40
4X = 56
X = 14

length is 14 ...... width is 6 YOU ARE RIGHT

2006-09-15 20:35:49 · answer #5 · answered by tchoocher 1 · 0 0

Yeah you're right. Perimeter of rectangle is 2(l)+2(w). Just sub in the two numbers and check your answer.

2006-09-15 23:20:27 · answer #6 · answered by hockey craze99 4 · 0 0

you are correct,

the perimeter 40 would equal 2X + 2(X-8)
4X=56
X=14
14-8=6

2006-09-15 20:32:45 · answer #7 · answered by Scott C 2 · 0 0

You forgot to add the abbreviation (cm.) but other than that, you got it right.

2006-09-15 21:34:37 · answer #8 · answered by Hidehiro 1 · 0 0

I think thats right

2006-09-15 20:27:04 · answer #9 · answered by Anonymous · 0 0

Yeap you've got it correct!!

2006-09-15 20:32:16 · answer #10 · answered by joey 2 · 0 0

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