2006-09-15 06:22:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Odd; there was a question worded just this way a couple of days ago, and it had too many carbons. This time there are too few. What's up?
Assuming that this time, like last time, what was meant is C4H9Br, there are 4 structural isomers:
1-bromobutane
2-bromobutane
1-bromo-2-methylpropane
2-bromo-2-methylpropane
The previous answerer is correct in that the second in this list has two stereoisomers, but stereoisomers are not structural isomers.
2006-09-15 06:57:53 · answer #1 · answered by Mr. E 5 · 0⤊ 0⤋
Did we forget our 2n + 2 rule, doc? I think that you mean C4H9Br.
The C2 compound has one, the C3 compound has two, and the C4 compound has five due to the chiral carbon on the n-butyl form.
2006-09-15 13:36:47 · answer #2 · answered by L96vette 5 · 1⤊ 0⤋
you have too many hydrogens on your structure
max # H = 2n+2
2(2) +2 = 6
2006-09-15 13:29:11 · answer #3 · answered by shiara_blade 6 · 0⤊ 1⤋
There is no such compound as "akyl bromide"
And no compound has the molecular formula C2H9Br.
2006-09-15 13:30:14 · answer #4 · answered by deflagrated 4 · 0⤊ 2⤋
You tell us
2006-09-15 13:23:41 · answer #5 · answered by Anonymous · 0⤊ 2⤋