An apple is thrown vertically downwardfrom a cliff 48 m high and reaches the ground 2s later. what was the apples initial velocity???
2006-09-15 05:13:07 · 5 answers · asked by anyONE 2 in Science & Mathematics ➔ Physics
The first thing you should do is DRAW the problem. After that, you can explain the problem.
Yinitial=Ymax=48m
a=g=9.807m/s2
Yfinal-Yinitial=(1/2)g*t2+V0*t
Since Yfinal=0,
solve the equation for V0 (V0=Vinitial) and that's it. It gets a negative value of the initial velocity, but remember the movement is downwards, and that is from the council about the negative sides (when Y goes down is negative).
2006-09-15 05:36:44 · answer #1 · answered by Calculus Teacher 2 · 0⤊ 0⤋
Compute the average velocity = 48/2=24m/s
Using the equation
v=(at+iv)/2
where
a=acceleration of gravity
t=time
iv=initial velocity
48=9.8*2+iv
48/19.6 = iv
2006-09-15 05:18:50 · answer #2 · answered by odu83 7 · 0⤊ 0⤋
use the equation
s =ut + 1/2at^2
where s is distance travelled
u is initial velocity which u need to calculate
a is acceleration due to gravity =9.8 m/s^2
t is time required to travel the distance=2s
answer is 14.2
2006-09-15 05:22:51 · answer #3 · answered by arvik_the_first 2 · 0⤊ 0⤋
s=ut+.5gt^2
so the initial velocity is approx 14m/s
2006-09-15 06:57:53 · answer #4 · answered by abinand 1 · 0⤊ 0⤋
14.2m/s
2006-09-15 05:21:31 · answer #5 · answered by THJE 3 · 0⤊ 0⤋