If sin0=0,
Opp.side/Hypotenuse=0
=> Op..side =0
=> the triangle does not exist
so how can sin0 degrees be defined?
Similiarly,
Cosec90 =1
=> Hypotenuse/opp.side =1
=> Hypotenuse = opp.side
which is impossible in a rt. triangle so how can such angles be defined?
2006-09-15 03:31:51 · 8 answers · asked by Knightmare 1 in Science & Mathematics ➔ Mathematics
we do not have a size of length be 0 but sin 0 is defined as a limit
as the size -> 0. By this analogy we cannot have trigonomertic ratio of angles out side 0 to 180 degrees. whenwe decrese the angle the opposite side keeps decreasing and sin theta keeps decreasinh. when angle is tending to zero then sin theta is zero in limiting case
2006-09-15 03:37:16 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
If you are talking of sin you are talking of a right triangle with hypotenuse = 1 always, in the case of one of its sides being 0 (the Y side) because the angle is 0, then the other side must be 1, wich is virtually the same line as the hypotenuse.
2006-09-15 10:46:59 · answer #2 · answered by alexqr79 2 · 0⤊ 0⤋
Yes - sin 0 = 0
Think of a triangle with side = 0.
Csc 0 = infinity because 1/0 = infinity
Csc 90 = 1 because 1/1 = 1.
2006-09-15 10:36:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Yes, Sin 0=0...
Why do you say that CSC 90=1 is false? If you use the unit circle, then you will find it is the case. See the link.
2006-09-15 11:03:17 · answer #4 · answered by S W 1 · 0⤊ 0⤋
If you have an angle of zero degrees, you have an opposite side of length zero. There is in reality no triangle.
2006-09-15 11:47:13 · answer #5 · answered by davidosterberg1 6 · 0⤊ 0⤋
You are right,sin0=0
But there are always degenerate triangles,which hava one side null
2006-09-15 10:36:18 · answer #6 · answered by ioana v 3 · 0⤊ 0⤋
Yes it is
2006-09-15 10:36:41 · answer #7 · answered by pitsomos 2 · 0⤊ 0⤋
yea
2006-09-15 10:39:29 · answer #8 · answered by ba0beix 1 · 0⤊ 0⤋