math hmwk. its really confusing and i have no idea how to do the second part of it... i got a, but i just dont get how to do b. which is forming the equation.... plz help me!
a rabbit can run 25 feet per second. a coyote that can run 50 feet per second spots teh rabbit and starts running. the coyote is x feet away from the rabbit, and the rabbit is 30 feet away from its burrow.
a. write expressioins for the time it will take the rabbit to get to its burrow and for the time it will take the coyote to get to the burrow.
rabbit-30/25
coyote-(x+30)/50
b. write and solve an equation that relates the two expressions in a.
2006-09-14 16:06:45 · 2 answers · asked by ladida 2 in Science & Mathematics ➔ Mathematics
i'm 13... and in 8th grade.
2006-09-14 16:09:02 · update #1
a) 30/25
b) (x+30)/50 Assuming that the coyote is not between the rabbit and the burrow!
30/25=60/50
(x+30)/50=60/50
x+30=60
x=60-30
x=30
I really don't know if this is right or not, though...
2006-09-14 16:21:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
thats hard.....how old r u....what grade
2006-09-14 23:08:37 · answer #2 · answered by penguin, or maniacle evil genius 3 · 0⤊ 0⤋