p(x) = (7x2) - (3x) + 2
p(3) = 14 -(3x3)+2
p(3) = 14-9+2
p(3) = 7
p = 7/3
p = 2.33
2006-09-14 15:58:07
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answer #1
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answered by Abrams Tanker 3
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this is a functions problem, so 'p(x)' is actually 'y'.
to solve this, we must change this general form equation into completing the square equation or as some people like to call it, vertex form.
p(x)=7x^2-3x+2 change the coefficient of x^2 to 1 by dividing the equation by 7, but leave out '+2', for if you don't, you will complicate things.
p(x)=7(x^2-3/7x+[(3/7)/2]^2-[(3/7)/2]^2 +2. add the square value of half of 3/7x and subtract it, so the equation does not change.
p(x)=7[(x-3/14)^2-9/49]+2 ah... i'm tired of explaining every step. sorry.
p(x)=7(x-3/14)^2-9/7+2
p(x)=7(x-3/14)^2-18/14+28/14
p(x)=7(x-3/14)^2+10/14
p(x)=7(x-3/14)^2+5/7
now, p(x) is y, 5/7 is k, 3/14 is h.
vertex is (3/14, 5/7), axis of symmetry is 'x=3/14'.
to get x-intercepts, use y-k=a(x-h)^2 equation. I'm not going to show you how. this answer is long enough already.
Edit: Oops, I didn't see the x=3...
Edit: You guys are all WRONG. That 7x2 is actually 7x squared, as in 7x to the power of 2, as in 7, variable x, and then squared, not 7 times 2, unless I misinterpretted it, but it's not my fault really.
2006-09-14 16:04:46
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answer #2
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answered by crackincello 1
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you put p(3)=7x2-3(3)+2
multiply (order of operations)
you should now have
p(3)=14-9+2
now subtract and add across from left to right
p(3)=5+2
p(3)=7
and thats your answer
you do mean by this problem 7 times 2 minus 3times x plus 2 correct because some other people think you mean 7 times x times 2 minus three times x plus two
2006-09-14 15:53:56
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answer #3
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answered by anne 2
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I just had that hw problem
p(3) = 7 X 2 - 9 +2
= 14 -7 = 7
2006-09-14 15:50:04
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answer #4
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answered by Manan T 3
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put x=3 in the equation.
p(x ) = 7*9-3*3+2
= 63 -9 +2
= 56.
2006-09-14 15:49:43
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answer #5
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answered by macline k 2
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14-9+2
7
2006-09-14 15:47:31
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answer #6
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answered by bibliophile31 6
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what number x^2s can we've? from 3x we get no x^2s from -4x(x + 2) we get -4x^2 from -3(x^2 -x) we get -3x^2 so in total we've (-4 + -3)x^2 = -7x^2 what number 'x's can we've? from 3x we get 3x from -4x(x + 2) we get -8x from -3(x^2 - x) we get (-3)(-x) = 3x so in total we've (3 + -8 + 3)x = (6 - 8)x = -2x So the respond is A. -7x^2 - 2x IPOD: the unique cost became better than $a hundred and sixty, in fact 20% extra. to function 20% to $a hundred and sixty, i might multiply a hundred and sixty * a million.20 = a hundred and sixty + 32 = $192.
2016-11-07 08:45:53
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answer #7
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answered by Anonymous
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7(3)2-3(3)+2=
42-9+2=
33+2
35
2006-09-14 15:53:52
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answer #8
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answered by timmytrunks 2
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you insert 3 into the equation where ever you see an x.
p(3)= 7(3)^2-3(3)+2
p(3)= 7(9)-9+2
p(3)=63-7
p(3)=56
2006-09-14 15:52:14
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answer #9
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answered by cinquefoil_solis 3
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7x2= 7times3times2=42
42-(3times3)+2
42-9+2
44-9
35
2006-09-14 15:55:51
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answer #10
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answered by BI - Health 1s 2
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