What is the acorn's velocity when it reaches the ground?
2006-09-14 15:37:43 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The equation would be 1/2at^2 + vt - c = 0
a = 9.81 m/s^2 (acceleration due to gravity)
v = 0 (initial velocity)
c = 8 (distance to fall)
so
1/2gt^2 = 8
(9.81 m/s^2) * t^2 = 16
t^2 = 1.63 sec^2
t = 1.28 seconds
Note: Sorry, had to correct the original question
2006-09-14 15:53:22 · answer #1 · answered by Slider728 6 · 0⤊ 1⤋
18
2006-09-14 15:45:39 · answer #2 · answered by hello_kitty_fan 2 · 0⤊ 0⤋
F=ma
the only force is the force of gravity, so F=-mg
-mg=ma
-g=a, so in other words it accelerates downward at the acceleration due to gravity
acceleration is the second time derivative of acceleration, so: a = dy^2/dt^2
dy^2/dt^2 = -g
Integrating with respect to t, we find:
dy/dt = -gt + C1, with C1 being equal to the initial velocity, which in this case is 0, so:
dy/dt = -gt
Integrating with respect to t, we find:
y = -1/2gt^2 + C2, with C2 being equal to the initial position, so:
y = -1/2gt^2 + 8
assuming g is 9.8m/s^2:
y = -4.9t^2 + 8
the ground is at y=0, so the acorn strikes the ground at y=0, so:
4.9t^2 = 8
t=1.278s
2006-09-14 15:54:40 · answer #3 · answered by poesraven8628 1 · 0⤊ 0⤋
someguy's reply is quite scientific although he overlooked one important detail: there could be a strong wind, lkie a hurrican which is actually the reason why the squirrel dropped the acorn, and therefore it could take much much longer before it touches ground...
2006-09-14 15:46:07 · answer #4 · answered by ceogero 3 · 0⤊ 0⤋
ok well. distance is 8m. initial velocity is 0m/s and the acceleration is 9.8m/s^2.
you have to find the time and the final velocity.
first, average acceleration is v2-v1/ t
9.8 = v2 / t
v2 = 9.8t
and average velocity * time is equal to the distance
v2+v1/2 * t = d
v2/2 * t = 8
v2 * t = 16(9.8t) * t = 16
t^2 = 16 / 9.8
t = sqrt (1.63...)
t = 1.2777 seconds
v2 = 9.8 * 1.2777 = 12.52m/s
2006-09-14 15:43:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋
acorn=8m. above ground
acceleration of gravity = 9.8m/s
8/9.8=0.82 seconds
2006-09-14 15:44:57 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the formula used is y=(1/2)gt^2
y=height, g=acceleration on earth= (9.8m/s^2) , t=time falling
thus, 8m=(1/2)(9.8m/s^2)(t)^2
then 8m/ ((1/2)(9.8m/s^2))=t^2
so 1.63265=t^2
square root both sides, then t=1.27775
2006-09-14 16:19:11 · answer #7 · answered by Double Century Dude 3 · 0⤊ 0⤋
The acorn is in the air until it hits the ground.
You're welcome.
2006-09-14 15:47:08 · answer #8 · answered by thatwench 5 · 0⤊ 0⤋
beats me lol
2016-12-12 22:03:46 · answer #9 · answered by Breanna 1 · 0⤊ 0⤋