how do you find "b" in y=mx+b?

Question

i tired.... is it
b= -1(mx-y) ???
or is it something else?
i forgot math over the summer :(

thank you everyone! you saved my homework.... i'll pick best answer later ;)

Answer 1

Yes, b = -1(mx -y)

In other words, b=y-mx

Just subtract "mx" from both sides. Thus, you get y-mx=b, which is written equivalently as b=y-mx, which is the same as b=-1(y-mx).

If you are referring to the graph of a line, "b" represents the y-value that the line crosses when it hits the y-axis (whre x=0). "b" is known as the "y-intercept" because of that. As you can see, if b=y-mx, when x=0, b=y, which is what you would expect.

Answer 2

If you have the value of m, y and x, then just solve for b algebracally.

If you only have 2 sets of y and x coordinate, just substitude them in the equation and solve for m and b variable.

Or if you have 2 sets of y and x coordinate, just draw a straight line in the graph whereby the value intercepting the y axis when x =0 is your value for b

hope this help

By the way, b suppose to be b = y-mx

Answer 3

Y Mx B

Answer 4

In the equation of a line, y=mx+b, m is the slope and b is the y-interecpt (where the line crosses the y axis).
y=mx-1

Answer 5

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RE:
how do you find "b" in y=mx+b?
i tired.... is it
b= -1(mx-y) ???
or is it something else?
i forgot math over the summer :(

Answer 6

subtract mx from both sides of the equation. you get:

y - mx = b

It's as simple as that.

Answer 7

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This is the answer: To put "x-2y=2" in "y=mx+b" form, you have to: x-2y=2 Subtract x on both sides of the equation. -2y=-x+2 Divide all variables on both sides of the equation by -2. y=x/2-2

Answer 8

y=mx+b
y-b=mx+b-b
y-b/y=mx/y
-b=mx/y
-b*-1= -(mx/y)
b=-(mx/y)

poo i idd it wrong im kinda tipsy sorry