The surface of Lake Michigan is 22,300 mi. 2(square). If the lake was a perfect circle what would its circumfurence be?
Tell me how you got the answer and thank you.
2006-09-14 15:29:41 · 5 answers · asked by Billy 1 in Education & Reference ➔ Homework Help
22300 / pi = 7098
square root( 7098) = 84.25 (radius)
84.25 * 2 * pi =
529.4 feet circumference
2006-09-14 15:39:01 · answer #1 · answered by Steven B 6 · 1⤊ 1⤋
You should know that the area of a circle is: pi x radius squared
And that the circumference is: 2 x pi x radius
So we have area which is 22,300.
So.... 22,300 = pi x radius
Solve this for the radius. (I'll let you do the math)
After you get the radius, plug it into the circumference.
Circumference = 2 x pi x radius
And the answer is the circumference of the lake! And circumference would be in miles.
Hope that is a better answer than someone just giving you the answer.
2006-09-14 15:40:43 · answer #2 · answered by Amanda 6 · 0⤊ 0⤋
Divide 22,300 by pi, then get the square root, mulitply by 2, then by pi again.
2006-09-14 15:39:30 · answer #3 · answered by honneebee68 2 · 0⤊ 0⤋
Man this is tough.
2006-09-14 15:37:06 · answer #4 · answered by Fadhl 3 · 0⤊ 2⤋
This is TOUGH...
2006-09-14 15:46:07 · answer #5 · answered by Anonymous · 0⤊ 1⤋