find the domain of 4x/x^2-16?

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find the domain of 4x/x^2-16?

2006-09-14 14:04:38 · 3 answers · asked by paulie2050 1 in Science & Mathematics ➔ Mathematics

3 answers

[-inf, 0), (0, inf).

That is, all real numbers except zero.

2006-09-14 14:08:04 · answer #1 · answered by jinxy 2 · 0⤊ 0⤋

first off remember that the denominator cannot equal zero

therefore x^2 - 16 <> 0, this is the difference of squares so..
(x - 4)(x + 4) <> 0

so. x <> 4, x <> -4

you're domain is ( -inf, inf +), x <> -4, 4

2006-09-14 21:17:20 · answer #2 · answered by Mark B 2 · 0⤊ 0⤋

(negative infinity, -4)U(-4,4)U(4, infinity)

2006-09-14 21:09:18 · answer #3 · answered by joe 1 · 0⤊ 0⤋