Density Chem Question?

Question

Equal masses of two liquids are mixed to give a solution of density 1.0374 g /mL. If the density of the first liquid is 0.9408 g/ mL, calculate the density of the second liquid in g /mL and round to the correct number of significant digits. Assume that the volumes are additive.

Answer 1

The mass of each liquid is set to X grams. The final mass = 2X grams.

If we look at X = 10.00 grams, the liquid 1 would have a volume =
10.00 g / 0.9408 g/mL = 10.629 mL

The final solution would have a volume =
20.00 g / 1.0374 g/mL = 19.279 mL

If the volumes were additive, the volume of the second liquid =
19.279 - 10.629 mL = 8.650 mL

The density of the second liquid = M/V
10.00 g / 8.650 mL = 1.156 g/mL

Answer 2

lets assume we have 1000,0g of each liquid
then you have 1000,0g* 1ml/1,0374g of X = 963,95mL of X
and 1000,0g of Y times 1mL/0,9408g = 1063,0mL of Y
then, volume X + volume Y= 2027,0mL of sollution, and since we have 2000,0g of sollution, you get a density of 0,98668g/mL of sollution

Answer 3

Density = Mass/Volume

1.0374 g /mL = (0.9408 + x)g/ mL

0.0966g/mL

I think that is the answer

Answer 4

DX = 0.9408 g/ ml
DY = ?
DF= 1.0374g/ml
V = volume

(V)(DY) + (V)(DX) = (2V)( DF)

(DY) = { (2V)( DF) - (V)(DX) } / V

plug in 5 ml for the volume and plug in the respective densities
Claculate your answer

Density of Y = 1.134 g / ml

then check the answer by doing the math.
it checks out.