tal as shown in Figure 6-21. Find the force necessary to start the crate moving, given that the mass of the crate is m = 33 kg and the coefficient of static friction between the crate and the floor is 0.50.
2006-09-14 13:30:05 · 3 answers · asked by Me 2 in Science & Mathematics ➔ Physics
First, break F into horizontal and vertical components
Fh = F cos 21
Fv = F sin 21
The total downward (vertical) force on the floor is
Fv + 33g = 33g + F sin 21
The frictional force is proportional to the total downward force. So the minimum horizontal force required to overcome friction is
Fh = F cos 21 = 0.50(33g + F sin 21) = 16.5g + 0.5 F sin 21
F(cos 21 - 0.5 sin 21) = 16.5g
F = 16.5g / (cos 21 - 0.5 sin 21)
F = 214.3 N
2006-09-14 15:55:17 · answer #1 · answered by bpiguy 7 · 3⤊ 0⤋
Large Crate
2016-09-29 04:03:54 · answer #2 · answered by ? 4 · 0⤊ 1⤋
I use a forklift.it does all the heavy thinking
2006-09-14 13:57:12 · answer #3 · answered by La-z Ike 4 · 1⤊ 5⤋
wrong higher three mexicans to do it for you for thirty bucks your welcome! LOL!
2006-09-14 13:38:05 · answer #4 · answered by Anonymous · 1⤊ 8⤋