y(y+8)=-27
2006-09-14 10:04:16 · 8 answers · asked by ruby 2 in Education & Reference ➔ Homework Help
then what is y?
2006-09-14 10:10:45 · update #1
y^2 + 8y + 27 = 0
You can't solve this as 8 and 27 don't have any common factors
2006-09-14 10:11:02 · answer #1 · answered by Philip W 7 · 0⤊ 0⤋
distriute y and then bring the -27 to the left said so that it reads like this: y^2+8y+27=0.... then you should be able to find the roots and solve for y.
2006-09-14 10:09:23 · answer #2 · answered by Lil Fetey 2 · 0⤊ 0⤋
times the y to all the numbers in parthese so it looks like y sq + 8y then bring the -27 over so it looks like y*2 + 8y + 27=0 the 27 becomes positive when you cross the equals sign.
2006-09-14 10:22:55 · answer #3 · answered by Anonymous · 0⤊ 1⤋
y^2 + 8y + 27 = 0
Use the quadratic equation to solve for y.
2006-09-14 10:13:43 · answer #4 · answered by Random Person 4 · 0⤊ 0⤋
1. multiply y by y and y by 8 (to get rid of the parenthises)
2. now you have 2y+8y=-27
3. add the like terms (2y and 8y)
4. you now have 10y= -27
5. divide -27 by 10 (to seperate the variable)
6. now you have y= -2.7
2006-09-14 10:14:13 · answer #5 · answered by Anonymous · 0⤊ 1⤋
You would multiply y by the variables in the parenthesis.
y(y+8)=-27
y^2 + 8y = -27
Hope that helped!
2006-09-14 10:08:50 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ok first you multiply the variables inside the parenthesis by y.....so you get ysquared+8y=-27...thats in its simplest form
2006-09-14 10:06:56 · answer #7 · answered by volllballgirl 3 · 0⤊ 0⤋
Use the quadratic formula.
2006-09-14 10:14:33 · answer #8 · answered by MACK92707 1 · 0⤊ 1⤋