try to get one of the variables to "disappear". looks like u can multipy the top equation by 2, in order to get 4x, and then subtract the 2nd equation to figure out y:
2(2x-3y)= 2(5000)
4x - 6y = 10,000 (now u SUBTRACT the 2nd formula)
-(4x- 5y = 45,000)
4x - 6y = 10,000
-4x + 5y = -45,000
_________________-
0x -1y = -35000
y = 35,000
plug in y=35000 to the 1st equation:
2x -3(35000) = 5000
2x - 105,000 = 5000
2x = 110,000
x = 55,000
check: 4(55,000) - 5(35,000) = 45000
220,000- 175,000 = 45,000
yay!
2006-09-14 09:45:28
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answer #1
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answered by sasmallworld 6
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2x-3y=5000 (eqn 1)
4x-5y=45000 (eqn 2)
multiply eqn 1 by 2 so that you create a 4x term. You want to use that to eliminate the 4x in equation 2 so that you only have a y = numbers type equation. Once you've worked out y you can put the value of y in one of the equations above to find x.
So eqn 1 times two gives you:
4x-6y=10000
Now take this new equation away from equation 2 to give you:
y=35000
put this value for y in eqn 1 and you get
2x-105000=5000
so 2x=110000
so x=55000
2006-09-14 09:49:13
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answer #2
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answered by Anonymous
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2x - 3y = 5000
4x - 5y = 45000
First, solve for x:
2x - 3y = 5000
2x = 5000 + 3y
x = (3y + 5000)/2
Then plug that value for x into your 2nd equation:
4((3y + 5,000)/2) - 5y = 45,000
12y/2 + 20,000/2 - 5y = 45,000
6y + 10,000 - 5y = 45000
y = 35,000
You have found y! Now, plug the value for y back in to the first equation, and solve:
2x - 3(35,000) = 5,000
2x - 105,000 = 5,000
2x = 110,000
x = 55,000
Voila!
2006-09-14 09:48:17
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answer #3
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answered by gburgmommy 3
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multiply first eqn by 2
4x - 6y = 10000
Take away from second
4x - 5y - 4x + 6y = 45000 - 10000
y = 35000
Substitute in first
2x - 105000 = 5000
2x = 110000
x = 55000
2006-09-14 09:44:44
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answer #4
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answered by Philip W 7
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Simultaneous equation I believe. Elimination method.
2006-09-14 09:41:20
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answer #5
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answered by Wolf 2
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sry i suck at those!
2006-09-14 09:42:21
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answer #6
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answered by Anonymous
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