The longest recorded skid marks on a public road were left by a jaguar in a 1960 auto accident in USA and measured an astounding 290 m long. Assuming that the car had an average accelaration of -3.9 m/s^2 determine the jaguar's initial speed before the skid started.
2006-09-14 09:19:06 · 4 answers · asked by Hamza 1 in Science & Mathematics ➔ Physics
i'm not going to solve it for you since i'm against doing other people's homework, but the equation you're looking for is this:
V(final) ^ 2 = (V(initial) ^ 2) + 2*A*d
where we know v(final) = zero, we know A = -3.9 and we know d = 290. now you just need to solve for V(initial)
2006-09-14 09:30:50 · answer #1 · answered by promethius9594 6 · 1⤊ 0⤋
Substituting the given figures into the formula V^2 = 2AS, we get 47.56 m/sec which converts to 106.4 mph, rather leisurely for a Jaguar.
The UK Highway Code gives a table of stopping distances which for that speed work out to 205 metres, but it does warn that skids take longer.
2006-09-14 16:44:13 · answer #2 · answered by bh8153 7 · 0⤊ 1⤋
On variable not included in you question is the angle of the road--i.e., what are the effects of gravity on deceleration. Also, given that the coefficient of friction between wheel and asphalt is also not motioned leads me to believe this is a High School Physics homework question. If so, then review the chapter you are working in and find a suitable equation.
2006-09-14 16:44:37 · answer #3 · answered by Anonymous · 0⤊ 1⤋
290 meters?!? wow... must have been one bad set of brakes... or tires
2006-09-14 16:21:59 · answer #4 · answered by arctic storm 1 · 0⤊ 1⤋