solve. x(2exponent)+3x-18=0
Thanks.
2006-09-14 08:48:37 · 8 answers · asked by Marie 3 in Education & Reference ➔ Homework Help
x = {-6, 3}
Now, how did I get there?
2006-09-14 08:52:08 · answer #1 · answered by credo quia est absurdum 7 · 0⤊ 0⤋
First you factor the equation. The factors would be: (x+6)(x-3)=0.
Then you seperate the factors: (x+6)=0 and (x-3)=0. Then you solve for x in both the factors. So, the final answers should be -6 and 3.
2006-09-14 15:51:42 · answer #2 · answered by frisbee72001 3 · 0⤊ 0⤋
x^2+3x-18=0
For equations like this, you use the quadratic formula:
x = (-b +/- (b^2 - 4ac)^1/2)/2a
for the equation ax^2 + bx + c = 0
a = 1
b = 3
c = -18
x = (-b +/- (b^2 - 4ac)^1/2)/2a
x = (-3 +/- (9 + 72) ^1/2)/2
x = (-3 +/- (81) ^1/2)/2
x = (-3 +/- 9)/2
x = -12/2 and 6/2
x = -6 and 3 (quadratic formula always yields 2 results)
2006-09-14 15:58:42 · answer #3 · answered by ³√carthagebrujah 6 · 0⤊ 0⤋
x= (3,-6)
2006-09-14 16:01:10 · answer #4 · answered by monicafranklin2 2 · 0⤊ 0⤋
(x+6)(x-3)
2006-09-14 15:59:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x2 + 3x - 18 will be factored out to:
(x +6) (x-3)
Since -6 won't work, then 3 is your answer
x = 3
2006-09-14 15:50:09 · answer #6 · answered by bigred8882 4 · 0⤊ 2⤋
Perhaps forego the Algebra for now and concentrate on the spelling. Good luck.
2006-09-14 15:51:19 · answer #7 · answered by babalu2 5 · 0⤊ 1⤋
You solve it
2006-09-14 15:49:36 · answer #8 · answered by Anonymous · 0⤊ 1⤋