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1 5 17 53 161...........
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2006-09-14 05:06:59 · 9 answers · asked by That One Guy 2 in Science & Mathematics Other - Science

9 answers

t1=1
t2=1+4*3^0=5
t3=1+4*(3^0+3^1)=17
t4=1+4*(3^0+3^1+3^2)=53
t5=1+4*(3^0+3^1+3^2+3^3)=161
Next term is 1+4*(3^0+3^1+3^2+3^3+3^4)=485

2006-09-14 05:10:29 · answer #1 · answered by astrokid 4 · 0 0

1, 5, 17, 53, 161, 324

1,5 ... 5 - 1 = 4 (4 * 3 = 12)
5, 17 ... 17 - 5 = 12 (12 * 3 = 36)
17, 53 ... 53 - 17 = 36 (36 * 3 = 108)
53, 161 ... 161 - 53 = 108 (108 * 3 = 324)

Hope this is right, was a challenge! Had to search the next for inspiartion and ways to solve for these answers.
Jennifer

2006-09-14 05:28:20 · answer #2 · answered by jennifermlayne 2 · 0 0

i will see that the 1st, third and so on. numbers multiply by using 3 every time. i will see that the 2d, 4th and so on. numbers subtract 2 every time. which might supply a continuation to the sequence: 2 9 6 7 18 5 fifty 4 3 162 a million 486... with fifty 4 the for the asked seventh term. even however, there are an endless form of formulae for the guy words which might supply any value to the seventh term!!!

2016-12-12 08:19:45 · answer #3 · answered by Anonymous · 0 0

485. each next number is 3 times as much as is in between the previous numbers added to the last number. um...5-1=4. so there's 4 in between 1 and 5. then 17-5=12 so there's 12 in between 5 and 17 which is 3 times 4 and so on.

sorry, my math was off.

2006-09-14 05:16:36 · answer #4 · answered by practicalwizard 6 · 0 0

485

2006-09-14 05:19:57 · answer #5 · answered by Anonymous · 0 0

485

2006-09-14 05:17:18 · answer #6 · answered by Charles B 4 · 0 0

121

2006-09-14 05:11:05 · answer #7 · answered by Reggie 3 · 0 1

485 smartass

2006-09-14 05:17:13 · answer #8 · answered by pollypureheart 4 · 0 0

485

the difference between adjacent numbers in the series is 4*3^n where n is the n'th number in the series... just so that you know i'm not copying :-P

2006-09-14 05:16:16 · answer #9 · answered by Shane 2 · 0 0

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