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2006-09-14 04:59:21 · 16 answers · asked by Anonymous in Science & Mathematics Physics

Your going in the right derection ;)

2006-09-14 05:46:46 · update #1

16 answers

I think you could make a good argument that you would weigh more at the poles for exactly that reason. The reason is that at the pole our tangental velocity is equal to 0. The sum of the Forces has to still be equal to zero so since there is no tangental velocity and no centrifugal force component. It has to be true and here is why. Why do objects orbit the earth? It is because they are moving at such tangental velocity that the centrifugal force is sufficient to overcome gravity just enough that the object misses the earth on its re-entry trajectory. I would imagine that if you were going fast enough (and omitted things like friction from air and such as they would make you incinerate) you could accelerate yourself fast enough so that you could orbit the planet only inches above the earth's surface.

In short...we weigh more at the poles.

2006-09-14 05:35:40 · answer #1 · answered by FilmfibrilProcess 1 · 1 0

The amount of gravity exerted on your body decreases exponentially as your center of mass moves away from the earth's center of mass. Since centrifigal forces expand the surface of the earth in the center, moving your masses apart, you will weigh less at the sea level on the equator where the expansion is greatest, and more at sea level at the poles where the distance is least. Ultimately, you will weigh the least at the point on the Earth farthest from the center (not necessarily the highest above sea level).

You are not made "lighter" by the centrifigal effect. The effect is perpendicular to the rotation, and the Earth is rotating on it's gravitational center, so there will be no countering lift against gravity from the centrifigal force.

2006-09-18 12:46:50 · answer #2 · answered by freebird 6 · 0 0

You do. The Earth bulges at the equator, so at the same elevation, you would be further from the center of gravity there (It's actually the center of both your and earth's gravity, but since you are so small compared to earth, you don't matter much).

Centrifugal force is a very confusing force and not really a real force. To the extent that it does exist, it is exerted on Earth, not you.

2006-09-14 08:27:06 · answer #3 · answered by dandandan 2 · 0 0

You do weight more at the pole. Or rather, you weight less at the equator due to centrifugal force. But the difference is extremely small, about one third of a percent, because the Earth is rotating too slowly for the centrifugal force to be very large.

2006-09-14 05:22:30 · answer #4 · answered by campbelp2002 7 · 0 0

1stly, it might be a little hard everyone, but our world isn't a perfect sphere. In fact, we are further from the centre of the earth at the equator than at the poles.

2ndly, we have very little mass, so the centripetal force that our true weight contributes to, is quite insignificant, so any weight difference would be fairly negligible, we are not exactly being flung out into outerspace when we go for a swim in the Pacific Ocean.

Finally, it'd be at least another 5 years before there is a fastfood restaurant at the poles.

Note: Our weight does vary around the world, but it just so happens that it is less dependent on the centripetal force and more on the distance from the centre of the earth.

2006-09-14 05:13:44 · answer #5 · answered by lkraie 5 · 0 0

The earth is not actually round, but slightly pear- shaped. Gravity is also not centrifugal, but is a quantum force and as such obeys a different set of laws. The laws that govern the Universe are layered much like the sets of laws we humans form within our societies. At the quantum level, Universal laws still apply, but now they are sub-divided, and more specific to specific circumstances and specific times. It's all kind of strange, while at the same time very elegant.

2006-09-14 05:38:36 · answer #6 · answered by ron k 4 · 0 1

not something says there won't be able to be. The universe is stranger than we may be able to imagine, as Oppenheimer stated. so some distance as all of us recognize, all count number is interested in different count number by employing gravity. This contains anti-count number, and darkish count number. Gravity seems a conventional resources of count number. If there develop into some style of count number that repelled different count number, that could want to be anti-gravity, in spite of the undeniable fact that it would want to be some diverse style of count number that no individual has ever detected. If it did exist, it would want to be questionable if shall we call it count number. on the different hand, it looks that the upward push of the universe is accelerating. that signifies that there might want to be a stress counteracting the stress of gravity, on the grounds that gravity might want to be slowing down the upward push. Cosmologists have proposed the existence of 'darkish capacity' because the source of this stress. If it exists, darkish capacity might want to nicely be an 'anti-gravity' stress. yet it really is all extraordinarily speculative. There might want to nicely be different causes for the sped up advance. it would want to easily be that we do not comprehend gravity as well as we anticipate of we do. when we communicate about the universe outdoors the photo voltaic gadget, we fairly do not recognize what is going on in any respect.

2016-11-26 23:03:53 · answer #7 · answered by powel 4 · 0 0

We will not weigh more anywhere on the earth because we were acted upon by the same gravitational acceleration. Weight is also dependent on mass and density, since our mass does not vary and so as we were on the same gravitational acceleration (that is by the earth) there is no change at all. But if the same mass will be brought to a different place with a different gravitational acceleration, weight will also change. Hope it helps.

2006-09-20 20:03:31 · answer #8 · answered by Jaimelson C 2 · 0 0

centrifugal force and gravitaional force are completely unrelated
doesnt matter how fast the earth is spinning
your weight depends on the product of the masses of the two objects(u and the earth)
F=GMm/r^2
and since ur weight can be considered negligible
g(gravity)= GM/r^2

2006-09-22 03:01:45 · answer #9 · answered by absentmindednik 3 · 0 1

Dan is correct. How much we weigh is a matter of how much gravity exists between ourselves and the Earth. That is determined by much distance there is between our center of mass and the Earth's and the mass of each. If the Earth was spinning twice as fast, it would have no effect on the amount of gravity you and the Earth exert on each other.

2006-09-14 05:07:25 · answer #10 · answered by yossarius 4 · 1 1

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