2006-09-14 04:41:17 · 7 answers · asked by frank castle 1 in Science & Mathematics ➔ Mathematics
Because both cos and sin have the range [-1,1], i.e. the most that they can be is 1. The only solution would be sinx=cosx=1, however this is not possible, cos is 1 for x=0 and sin is 1 for x=pi/2.
You can also see that cosx=sinx=1 is impossible from sin^2x+cos^2x=2, and the well known identity says sin^2x+cos^2x=1.
2006-09-14 04:47:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
because cosx and sinx have a maximum value of 1 and when cosx is maximum 1 sinx is minimum 0 and vice versa.so together they can never add upto 2
2006-09-14 04:44:12 · answer #2 · answered by raj 7 · 0⤊ 0⤋
the maximum value of cosx is 1
the maximum value of sinx is 1
but the values of x at which they give 1 are different So the sum cannot equal 2.
2006-09-14 04:49:26 · answer #3 · answered by Mike 5 · 0⤊ 0⤋
The maximum value for sine of anything is 1. The maximum value for cosine of anything is one. Sine and cosine are offset from each other so they could not both be at a maximum at the same time. Since they both can't be at 1 adding up to 2 that is impossible.
2006-09-14 04:46:04 · answer #4 · answered by Rich Z 7 · 0⤊ 0⤋
because if cos x=1 then sin x =0
2006-09-14 04:44:10 · answer #5 · answered by k_e_p_l_e_r 3 · 0⤊ 1⤋
it has no real solution, however IMHO there is a complex solution of the type
x = -i*ln(y+iy) where i=sqr(-1)
a quick calculation gives me y=1±(1/sqr(2))
2006-09-14 05:19:47 · answer #6 · answered by deflagrated 4 · 0⤊ 0⤋
because there is no specified value for x :)
2006-09-14 04:42:54 · answer #7 · answered by robbyack2000 2 · 0⤊ 1⤋