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20 answers

Let the cost of the case be x. Then the binoculars cost x+50. So the total cost is x+x+50=60. Subtract 50 from both sides: x+x=10, therefore x=5. The case costs £5.

2006-09-14 04:07:45 · answer #1 · answered by Steve-Bob 4 · 0 0

The case costs £5.

If binoculars cost £50 more than the case, then the binoculars cost £55 and the case costs £5, making the total £60.

2006-09-14 11:01:34 · answer #2 · answered by ajw121212 1 · 0 0

£5

2006-09-14 10:54:10 · answer #3 · answered by ? 4 · 0 0

Binoculars £55
Case £5

2006-09-14 10:55:10 · answer #4 · answered by Gem 3 · 0 0

case costs £5

2006-09-14 15:56:01 · answer #5 · answered by Daddybear 7 · 0 0

binoculars are 55, case is 5!!

2006-09-14 11:04:30 · answer #6 · answered by Anonymous · 0 0

£40

2006-09-14 11:06:13 · answer #7 · answered by Anonymous · 0 0

Let x = price of case, x + 50 = price of binaculars,
pribe of case + price of binacular = 60
x + x +50 = 60
2x = 60 - 50
x = 5

2006-09-14 11:05:59 · answer #8 · answered by Daniel Ira L. Cuevas 2 · 0 0

£60. You can't buy them separately, mfg policy. The difference is profit, I guess... What size binoculars are we talking about?

2006-09-14 11:20:04 · answer #9 · answered by Erica C 2 · 0 0

let the cost of binocular be £x
let the cost of case be £y

x+y=60..............equation 1
x-y=50...............equation 2

adding equation 1& 2

2x=110
therefore x=55
and y=5

therefore.......binoculars cost £55 and case cost £5

2006-09-14 11:08:12 · answer #10 · answered by Gaurab N 3 · 0 0

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