Distance = rate x time the anser is 4hrs........But how I have no IDEA.....
2006-09-14 03:37:04 · 6 answers · asked by Bibi 2 in Science & Mathematics ➔ Mathematics
Since, when the second train passes the first, they must have travelled the same distance, you can make the following equation, where t is the time in hours:
Distance = 60*t = 45*(t + 1.5)
60t = 45t + 67.5
Subtract 45t from both sides,
15t = 67.5, t = 4.5 hours. (and they will have both travelled 270 miles).
2006-09-14 03:48:40 · answer #1 · answered by Owlwings 7 · 1⤊ 0⤋
Plot a graph:
2006-09-14 05:03:17
·
answer #2
·
answered by bostoncity_guy 2
·
0⤊
0⤋
Time(in hrs)Distance (T2)Distance (T2)
0 00
0.5 22.5 0
1 45 0
1.5 67.5 0
2 90 30
2.5 117.5 60
3 140 90
3.5 162.5120
4 185 150
4.5 207.5180
5 230 210
5.5 252.5240
6 275 270
6.5 297.5300
6.75 308.75 315
7 320 330
As you see the graph lines will cross somewhere between 6 and 6.5 hrs, when T2 has covered 275
It develop into the day my dad died - i develop into 6. I save in concepts doing a Victoria Plum puzzle and a chunk develop into lacking. It develop into in basic terms later that I drew the analogy from it. The lacking piece from my existence.
2016-11-26 22:57:14 · answer #3 · answered by ? 4 · 0⤊ 0⤋
4.5 Hours
T2 is 67.5 miles down the track
T1 is traveling 15 mph faster.
67.5/15=4.5
2006-09-14 03:40:16 · answer #4 · answered by tyron01 2 · 0⤊ 1⤋
the answer is something between 1 second and 5 years... im not lying...
2006-09-14 03:47:04 · answer #5 · answered by Anonymous · 0⤊ 1⤋
revise on your rate, ratio & proportion topic.. And you will definitely get an answer...
2006-09-14 03:40:00 · answer #6 · answered by dada 2 · 0⤊ 1⤋