a.14,412
b. 28,734
c. 53, 796
d. 17,548
e. 38,888
2006-09-14 02:11:57 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
d and e. neither is divisible by 3, so they can't be divisible by 6.
Without a calculator, you can quickly tell this by summing the digits in the number. If the sum is not divisible by 3, then the original number is not.
ex. 14,412 --> 12 which is divisible by 3
ex. 17548 --> 25 which is not divisible by 3
Aloha
2006-09-14 02:22:52 · answer #1 · answered by Anonymous · 2⤊ 0⤋
If a number is divisible by 6, it is divisible by 2 and 3. All these numbers are divisible by 2, and so which one is divisible by 2?
Remember if you sum the digits of a number the result will be divisible by 3 if your original number was divisible by 3.
a. 1+4+4+1+2=12=3*4
b. 2+8+7+3+4=24=3*8
c. 5+3+7+9+6=30=3*10
d. 1+7+5+4+8=25
e. 3+8+8+8+8=35
So we can conclude that the last two numbers are indivisible by 3, and hence are indivisible by 6.
2006-09-14 09:30:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(d) & (e).
For (d)'s case, 17,548 divided by 6 is:
2924.666666666666666666666666666
For (e)'s case, 38,888 divided by 6 is:
6481..333333333333333333333333333
2006-09-14 09:19:56 · answer #3 · answered by happy_face95 1 · 0⤊ 0⤋
d and e do not have 6 as a factor.
2006-09-14 09:16:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
options d and e, you can easily tell by considering the digit sum for divisibility by 3, since all are easily seen as even (by checking the last digit)
check,
http://mathworld.wolfram.com/DivisibilityTests.html
2006-09-14 09:50:29 · answer #5 · answered by yasiru89 6 · 0⤊ 0⤋
D and E
2006-09-14 09:16:13 · answer #6 · answered by bruinfan 7 · 0⤊ 0⤋
(d) as it doen't add upto 3
2006-09-14 09:16:03 · answer #7 · answered by raj 7 · 0⤊ 0⤋
d
2006-09-14 09:15:45 · answer #8 · answered by josephus_einstein 2 · 0⤊ 0⤋
I think it is d. 17584
2006-09-14 09:31:24 · answer #9 · answered by Tired Old Man 7 · 0⤊ 0⤋
d) 17,548
2006-09-14 09:19:54 · answer #10 · answered by vani3624 3 · 0⤊ 0⤋