geometric progression?

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geometric progression?

2006-09-14 01:53:00 · 4 answers · asked by arwa d 1 in Science & Mathematics ➔ Mathematics

4 answers

what is the question?

2006-09-14 01:57:04 · answer #1 · answered by raj 7 · 0⤊ 0⤋

the nth term can be define as Tn = ar^(n-1)
the sum of the geometric progression is Sn = a(1-r^n)/(1-r)
the sum to infinity is S = a / (1-r), where r > 0

a = 1st term of the series
r = common difference

2006-09-14 02:40:17 · answer #2 · answered by superlaminal 2 · 0⤊ 0⤋

It is when each new term is the previous term multiplied by some number. For example, 1,2,4,8,16,32....

2006-09-14 02:14:34 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋

gfwx
Answer to you invisible question

2006-09-14 02:09:47 · answer #4 · answered by roshan 1 · 0⤊ 0⤋