2006-09-14 01:46:07 · 5 answers · asked by unquenchablethirst 2 in Education & Reference ➔ Homework Help
5 + px - x^2 = 9 - (x^2 +2qx + q^2)
5 + px - x^2 = 9-q^2 - 2qx - x^2
Therefore:
5 = 9-q^2
q^2 = 4
q = 2
and:
p = -2q
p = -2*2
p = -4
2006-09-14 01:53:48 · answer #1 · answered by T 5 · 0⤊ 0⤋
=> x^2 - px + 4 = x^2 + 2qx + q^2
can be taken with a little manipulation, (i.e expand backets move known numerical constants to LHS and divide by -1)
then -px +4 = 2qx + q^2
equating constants,
q^2 = 4
q = 2 or -2
p = -2q = 4 or -4
voila!
2006-09-14 02:15:19 · answer #2 · answered by yasiru89 6 · 0⤊ 0⤋
put x=0 5=9-q^2
q^2=4
so q=+/-2
put x=1
5+p-1=9-(1+/-2)^2
p=5-1=4 or 9-9=0
so p can have two values +/-2 and the corresponding values for q will be 0 or
2006-09-14 01:54:25 · answer #3 · answered by raj 7 · 0⤊ 0⤋
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2016-11-26 22:48:11 · answer #4 · answered by ? 4 · 0⤊ 0⤋
What the HELL
2006-09-14 01:54:39 · answer #5 · answered by boyzrkool 1 · 0⤊ 0⤋