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Find the value of
i ^ i

Where i = sqrt(-1)

^_^

2006-09-14 00:56:20 · 6 answers · asked by kevin! 5 in Science & Mathematics Mathematics

6 answers

simple

e^(pi * i) = -1
take square root

i = e^(pi * i/2)

i^i = e^(pi *i/2 *i) = e^(-pi)

2006-09-14 01:08:52 · answer #1 · answered by Mein Hoon Na 7 · 0 1

i^i where i=-1 =1 -1^-1=1

2006-09-14 01:29:22 · answer #2 · answered by spotlight 1 · 0 0

According to my TI-83, it's 0.2078795764

2006-09-14 02:12:41 · answer #3 · answered by Jason J 2 · 0 0

check out Imaginary numbers.

2006-09-14 00:59:51 · answer #4 · answered by Thou Shalt Not Think 3 · 0 0

it is +/-1 depending on even or odd factors

2006-09-14 01:01:02 · answer #5 · answered by raj 7 · 0 0

The answer is e^(-pi/2).

2006-09-14 02:18:17 · answer #6 · answered by bruinfan 7 · 2 0

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