the first floor of a home has a floor plan with 3 rooms. basically, there are 3 squares, and you have to find an expression in standard form.
square 1: W=2x L=x
square 2: W=x/2 L=x/2
square 3: W=x-5 L=6
2006-09-13 19:09:30 · 4 answers · asked by booo 1 in Science & Mathematics ➔ Mathematics
please explain how you got your answer :)
2006-09-13 19:16:11 · update #1
square 1: W=12 L=6
square 2: W=3 L=3
square 3: W=1 L=6
2006-09-13 19:14:51 · answer #1 · answered by fAr stAr 5 · 0⤊ 1⤋
If these are squares, how can the length be x and the width be 2x? If the width is twice the length, it's not a square.
That aside, I came up with the similar answer above:
A = (square 1) + (square 2) + (square 3)
A = (2x)(x) + (x/2)(x/2) + (x-5)(6)
A = 2x² + (1/4)x² + 6x - 30
A = (8/4)x² + (1/4)x² + 6x - 30
A = (9/4)x² + 6x - 30
2006-09-14 02:25:47 · answer #2 · answered by deathbywedgie 3 · 1⤊ 0⤋
Ok......
the formula for area is length times width...
(x-5)6 equals 6x-30, so you can set this equal to zero, so x equals 5... therefore, the area of square 3 is 0...
square 2
L X W
(x/2) * (x/2) equals x squared over 4, so the area of the second square is 25/4
square 1
the area is 2 x squared, which gives you 50.....
hope that was helpful, although i didnt quite understand what you were asking
2006-09-14 02:18:54 · answer #3 · answered by BigDaddy1 2 · 0⤊ 1⤋
I assume you're looking for an expression for the total area, yes?
The area of square 1 is 2x^2
The area of square 2 is (1/4)*x^2
The area of square 3 is 6x - 30
Add them all together to get a total area of:
(9/4)*x^2 +6x -30
2006-09-14 02:15:51 · answer #4 · answered by Bramblyspam 7 · 1⤊ 0⤋