two persons start the jorney from two different point A & B in opposite direction. and meet them after 1 hr of their jorney. afert the meeting the person came from A, reachs the point B in half an hour. the distance between A & B is 9 km. then what are the velocities of the two persons?
2006-09-13 19:02:48 · 8 answers · asked by Anonymous in Education & Reference ➔ Primary & Secondary Education
distance between the points is 9 km
their relatine velocity is 9 kmph as they are moving in the opposite directions the velcities will get added up
ther speeds are in the ratio of 2:1 and so
their speeds are 6kmph and 3kmph
person from A would have covered a distance of 6 km and B 3 km
remaining distance for the person from A to reach B is 3 km for which he would take 1/2 hr @ 6 kmph
2006-09-13 19:29:44 · answer #1 · answered by raj 7 · 1⤊ 0⤋
person starting from A first as more info is given on him:
He travels 9 km in one and a half hours so his velocity is
s = d/t = 9 /1.5 = 6 km/hr in the direction AB
Now A met B after one hour so ,
Since (the person from) A travels at 6 km/hr then he had covered 6 km of the distance between them so (person from) B travelled the remaining distance , i.e. 3 km in one hour and so his velocity is 3 km/ hr in the direction BA.
2006-09-14 17:15:13 · answer #2 · answered by jazideol 3 · 0⤊ 0⤋
9 KM a hr
2006-09-14 09:20:52 · answer #3 · answered by bkbarile 5 · 0⤊ 0⤋
6 km/hr u didnt put a specific direction
2006-09-13 19:06:43 · answer #4 · answered by duy n 2 · 0⤊ 0⤋
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2016-12-12 08:09:25 · answer #5 · answered by ? 4 · 0⤊ 0⤋
6 km/hr
2006-09-14 03:56:38 · answer #6 · answered by S_K_I_ 1 · 0⤊ 0⤋
use the formula- speed= distance\ time.
2006-09-15 02:26:16 · answer #7 · answered by Scoob 3 · 0⤊ 0⤋
6km/hr
2006-09-14 05:13:15 · answer #8 · answered by soundalonedrummer 2 · 0⤊ 0⤋