Electrical Engineering Problem from Basic Circuit Theory class. Can you solve it?

Question

Electrical Engineering Question?
I am taking a circuit theory class at UMD. Any EE in the house?

So suppose you have a voltage source Vs which has some internal resistance, Rv, running DC power connected in series with a single resistor, R1.

The questions my professor is asking are the following: 1) what should the load resistance be in order for the power to be maximized? and 2) what is that maximum value of that power?

The professor says we can use numbers for "partial credit". I'm thinking this question involves some type of trick. I mean, I suspect the power on the resistor is going to be P = (V^2)/Req, where Req is the sum of the resistances of the internal resistance of the voltage source, Rv, and the resistance of the resistor, R1.

Answer 1

Well, number 1 should be simple if you remember a rule of thumb, but you can derive it also. I would hope you know how to find power in the resistance R1, as a function of R1, Rv, and Vs. Then you need to find the value of R1 that maximizes the power. Once you have part 1 then part 2 should be easy. Perhaps this problem is meant to teach you the rule of thumb. Take a stab at it and put your result in the question, and I'll tell you if you are on the right track. Can't just give you the answer you know.

Answer 2

To do maximum concern-unfastened electrical energy all you will possibly % to be responsive to is Ohm's regulation it is V= I * R (Voltage = modern * Resistance). Resistance in an common circuit is calculated reckoning on how the circuit is desperate up. in case you have resistors in series then you relatively basically upload up the resistances to get to total resistance. in case you have resistors in parallel then you relatively upload up the inverses of of the resistances and take the inverse of the answer to locate the entire resistance. Ex. A 2 Ohm and a 4 Ohm resistor in parallel could be an entire resistance of: (a million/2) + (a million/4) = 3/4 ..... 4/3 ohms.