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I am doing IB Physics and I am having trouble getting the answer to this question.

Write an algebraic expression for the velocity of a uniformly moving object in terms of x, delta-x, t, and delta-t.

I would appreciate some help, thanks in advance!

2006-09-13 17:44:55 · 3 answers · asked by Anonymous in Education & Reference Homework Help

3 answers

uummm ok

velocity is the change in distance (over) the change in time agree?...like 60 miles per hour...

so it would be the change in x, which is delta x
divided by the change in t, which is delta t.

so the expression would look like the following:

(delta x) = { x (final) - x (initial)}
*velocity = ______ = ______________
(delta t) = { total time (t) }

2006-09-13 17:52:44 · answer #1 · answered by Anonymous · 1 0

In the case of uniform motion, velocity is defined as delta-x/delta-t; so the equation for velocity does not depend on x or t (that's what uniform means), and

v = delta-x/delta-t

The postion of the moving object x is given by velocity times time (t),

So x = (delta-x/delta-t)*t

2006-09-14 01:42:38 · answer #2 · answered by gp4rts 7 · 0 0

poop+s*it +pee+POOPIE

2006-09-14 00:55:41 · answer #3 · answered by SOADfan 2 · 0 1

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