A travel agency offers two Boston outtings. Plan A includes hotel accomodations for three nights and two pairs of baseball tickets worth $645. Plan B includes hotel accomidations for five nights and four pairs of baseball tickets worth $1135.
Let x represent the cost of one night's hotel accomidation and let y represent the cost of one pair of baseball tickets. Write a system of equations you could solve to find the cost of one night's hotel accomidation and one pair of baseball tickets. solve the system.
2006-09-13 17:33:15 · 3 answers · asked by sonovabeeech 1 in Science & Mathematics ➔ Mathematics
check the math book
2006-09-13 17:35:17 · answer #1 · answered by kandy 2 · 0⤊ 0⤋
3x + 2y = 645
5x + 4y = 1135
Multiply top by -2
-6x - 4y = -1290
5x + 4y = 1135
-x = -155
x = 155
3x + 2y = 645
3(155) + 2y = 645
465 + 2y = 645
2y = 200
y = 100
$155 for a one night's stay
$100 for each pair of baseball tickets
2006-09-14 03:04:49 · answer #2 · answered by Sherman81 6 · 0⤊ 0⤋
A: 3x + 2y = 645
B: 5x + 4y = 1135
To solve it, double equation A to be:
6x + 4y = 1290
Then subtract equation B:
6x + 4y = 1290
-5x - 4y = -1135
x = ...
Then you plug into one of the other equations to find the value of y.
2006-09-14 00:36:00 · answer #3 · answered by Doug 2 · 0⤊ 0⤋