Car wit velocity of 27 m/s slows down at a rate of -8.5 m/s a stop in a distance of 43 m on a road theres more

Question

road the same care traveling +27 m/s slows down at a rate of -6.5 m/s^2 to a stop on the same road
How much farther does the car travel on the road before coming to a stop
What maximum car speed will allow the car traveling on the road to stop in a distance of 43 m

Answer 1

v² = v0² - 2ax where v is final velocity, v0 is initial velocity, a is deceleration, and x is distance.

Now dig out your calculator and **work** the problem ☺


Doug