2006-09-13 16:58:31 · 4 answers · asked by je suis tres desole 2 in Science & Mathematics ➔ Mathematics
(x^2 - 2x - 8) can be factored as
(x - 4)(x + 2)
If x>4 or x<-2, the factors have the same sign and you can drop the absolute value. In between, the sign must be flipped. Therefore one possible answer is
= (x - 4)(x + 2) if x > 4 or x < -2
= -(x - 4)(x + 2) if -2 <= x <= 4
2006-09-13 17:05:15 · answer #1 · answered by dutch_prof 4 · 0⤊ 0⤋
The usual way (if I understand your question) is to write
|(x² - 2x - 8)| where the verticle bars mean 'absolute value'.
Doug
2006-09-13 17:20:51 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
Reduction? l(x-4)(x+2)l = '1n'. This leaves little doubt that the value is pos.
2006-09-13 17:14:37 · answer #3 · answered by cherodman4u 4 · 0⤊ 0⤋
would it be (x+x-2x-8) again i don't know I hate math just trying
2006-09-13 17:03:08 · answer #4 · answered by sweetlee725 2 · 0⤊ 0⤋