While descending at a constant speed of 1.0 m/s a scuba diver releases a cork, which accelerates theres more?

Question

accelerates upward at 3.0 m/s^2 What is the diver's depth when the cork reaches the surace 2.0 s later

Answer 1

Allright, we know acceleration of the cork, initial speed of the cork (1 m/s down), and time to hit surface. We do _not_ know starting depth of the cork. We need to figure that out. 2 seconds later, the diver will be 2 m deeper then the initial depth of the cork.

You've probably seen the formula for motion acceleration/2 X t^2 + initial velocity X t + initial position. (if/when you hit calculus, that's actually just accleration = a constant integrated twice with respect to time .... anyway)

we know that 3/2X t^2 + (-1)Xt - initial depth = 0 when t = 2 (i assume initial depth is less then 0, and the -1 represents moving down 1 m/s initially).

sot ... 3/2X2X2 -1X2 = initial depth
initial depth is 4.

2 seconds later, diver is 6 m down.

Answer 2

11 m

Answer 3

These are all nonsense questions from josh. Don't answer them. It will only encourage him.

Answer 4

I don't know what the hell your talking about but I wanted to post because you have my name.