A golfball leaves a tee at a speed of 2.0x10^2 km/h after being accelerated for .56 ms theres more?

Question

What is the ball's average speed in m/s^2
How far does it move in this time interval

Answer 1

200 kph=55.6m/s. To reach this speed from rest in 0.56ms, it needs an average acceleration, not speed, of 55.6/0.00056=100 000 m/s^2. The distance it's moved=v^2/2a=3091/200000=1.5 cm.

Answer 2

do you know the m1m2 formula conversion..? It is 67 mph..

But if you need this for a paper you have to writ edown the formula and dont forget to change kmh to mph.
You can actually take the free fall formula and get the same answer once adding 12 to the last number. but thats a different subject/.....Now give me my 10 pts