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2006-09-13 16:50:30 · 24 answers · asked by britiani j 1 in Science & Mathematics Mathematics

24 answers

subtract 4 from each side

2=-2x

divide both sides by -2 to isolate the variable

x=-1

2006-09-13 16:52:28 · answer #1 · answered by tplanningstages 1 · 0 0

1

2006-09-13 23:51:46 · answer #2 · answered by imjoshdotcom 2 · 0 1

X = -1

2006-09-13 23:51:59 · answer #3 · answered by tagi_65 5 · 0 0

x= - 1

2006-09-14 04:44:38 · answer #4 · answered by sweetangel 2 · 0 0

To solve for x:
6 = 4 - 2x (moved 4 to d other side & dont 4get 2 change d sign)
6 - 4 = -2x
2 = -2x
2/(-2) = x
-1 = x


So x is -1

-good luck-

2006-09-14 00:45:56 · answer #5 · answered by Anonymous · 0 0

6 = 4 - 2x

Here we go:
6 - 4 = 4 - 2x - 4
2 = -2x
2 / -2 = -2x / -2
-1 = x

So x = -1. Let's check the problem by plugging in the answer:

6 = 4 - 2 (-1)
6 = 4 - (-2)
6 = 4 + 2
6 = 6

So yup, yup, this works!

2006-09-14 00:15:32 · answer #6 · answered by ashcatash 5 · 0 0

First bring the 4 to the other side and subtract from the six.
6-4= -2x
2 = -2x
Next, divide both sides by -2.
2/-2 = -2x/-2
-1 = x
Then x = -1

2006-09-13 23:55:46 · answer #7 · answered by Anonymous · 0 0

Seriously , you should be able to solve these questions in less time then it takes to ask them here.

Do the same thing to both sides of the equation until 'x' is all on its own.

In this case, you'd start off by subtracting 4 from both sides, getting to 2 = -2x, then continue.

Not only are you avoiding learning something that you actually do need to know in life, but this is taking even longer then solving them would.

2006-09-13 23:55:20 · answer #8 · answered by kheserthorpe 7 · 0 0

6 = 4 - 2x
subtract 4 from both sides
2 = -2x
divide both sides by 2
x = -1

2006-09-13 23:54:37 · answer #9 · answered by searchpup 5 · 0 0

6 = 4-2x

Therefore,
-2x = 2
2x = -2
x = -1

x = -1 because

6 = 4-(-2)
6 = 4+2

Yepp :D

2006-09-14 00:32:45 · answer #10 · answered by b0b0link 2 · 0 0

6-4= -2x : 2=-2x : -1=x

2006-09-13 23:52:51 · answer #11 · answered by Scout Finch 2 · 0 0

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