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I would really just like some help in knowing the process of how to do this problem...Thank you!

2006-09-13 15:57:02 · 2 answers · asked by Kristyn P 1 in Science & Mathematics Chemistry

2 answers

0.370 moles sample has 3 atoms of O, so total moles O would be 0.370 * 3=1.11 moles O. Also, if you take 55.4 g/0.370 mole, you can derive the formula weight of the metal oxide, which would be about 149.7 . Subtracting the 16*3 (formula weight of oxygen) from that, you come out with just over 101. Half of that would be 50.9 or so. I'd bet the compound is V2O3 (vanadium oxide). Cheers!

2006-09-13 16:21:32 · answer #1 · answered by Black Dog 6 · 0 0

take the moles of metal oxide and multiply by the number of oxygen atoms in the formula (3 because of the subscript after the O) so .37(moles M2O3) * 3 O atoms per M2O3 = 1.11 moles of O

2006-09-13 23:01:24 · answer #2 · answered by metatron 4 · 0 0

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