dimensions of the rectangle?
2006-09-13 15:43:13 · 7 answers · asked by suly m 1 in Education & Reference ➔ Homework Help
L=2W+2
Permeter = 2L+2W =34
Substitute for L
2(2W+2)+2W = 34
4W+4+2W=34
6w=30
W=5
L=12
So 5 In X 12 in.
2006-09-13 15:49:49 · answer #1 · answered by just♪wondering 7 · 0⤊ 0⤋
Let the Width of the rectangle be W,
The Length, L = 2W + 2
The Perimeter is,
2L + 2W = 34
2(2W + 2) + 2W = 34
4W + 4 + 2W = 34
6W = 34 - 4
6W = 30
W = 5
Therefore,
L = 2W + 2
= 2(5) + 2
= 12
The dimensions of the rectangle is 12" x 5"
2006-09-13 23:01:09 · answer #2 · answered by ideaquest 7 · 0⤊ 0⤋
Let the width be X
hence the length = 2x + 2
Perimeter = 2( x + 2x + 2)
34 = 2 ( 3X + 2 )
17 = 3x +2
15 = 3x
X = 15 / 3 = 5.
length = 2* 5 +2 = 12 in. width = 5in.
2006-09-13 22:51:47 · answer #3 · answered by macline k 2 · 0⤊ 0⤋
L=12
W=5
2006-09-13 22:48:45 · answer #4 · answered by Steve-Ohhhh 2 · 0⤊ 0⤋
P = 34 in.
L = 2W + 2 in.
P = 2W + 2L
P = 2W + 2(2W + 2 in.)
P = 2W + 4W + 4 in.
P = 6W + 4 in.
34 in. = 6W + 4 in.
30 in. = 6W
W = 30 in. / 6
W = 5 in.
So, L = 2 x 5 + 2, or 10 + 2, or 12 in.
So, L = 12 in. and W = 5 in., cuz 2 x 12 + 2 x 5 = 24 + 10, or 34in.
Slow enough for you?
2006-09-13 23:01:43 · answer #5 · answered by nomad 3 · 0⤊ 0⤋
if width = x, then length = 2x+2
perimeter = 2x+2(2x+2)=34
2x+4x+4 = 34
6x = 30
x = 5
width = 5", length = 12"
2006-09-13 22:47:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋
where width is x and length is 2x-2
2(x)+2(2x+2)=34
2x+4x+4=34
-4 -4
6x=30
x=5
width is 5
length is 12
hope this helps!
2006-09-13 22:49:24 · answer #7 · answered by afireinsideme [DF] 6 · 0⤊ 0⤋