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2006-09-13 15:38:07 · 7 answers · asked by Lavonte G 1 in Education & Reference Homework Help

7 answers

2/3x -3 = 1/3 x
2/3x - 3 - 1/3x = 1/3x - 1/3x
1/3x - 3 = 0
1/3x = 3
1/3x * 3 = 3 * 3
x = 9

But you really need to start doing your OWN homework!!

2006-09-13 16:10:10 · answer #1 · answered by ashcatash 5 · 0 0

Ouch, it pains me to see so many people missed the key word "quantity". The problem should look like this:
2/3 (x-3) = 1/3x

Using the distributive property, you must multiply 2/3 by both things inside of the parentheses (both x and -3). The equation now looks like this:
2/3x -2 = 1/3x

Subtracting 1/3x from both sides gives you this:
2/3x - 1/3x - 2 = 1/3x - 1/3x
1/3x - 2 = 0

Add 2 to both sides:
1/3x - 2 + 2 = 0 + 2

Which leaves:
1/3x = 2

Divide both sides by 1/3, and you get the following:
1/3x / (1/3) = 2 / (1/3)
x = 2 / (1/3)
x = 2 times 3/1 (I inverted the fraction (flipped it over)... dividing by 1/3 is the same as multiplying by 3/1)
x = 6/1
x = 6 (Your answer)

To check:
Your originial equation: 2/3 (x-3) = 1/3x
Plug in 6 for x and make sure both sides are equal
2/3 times (6-3) = 1/3 times 6
2/3 times (3) = 2
2 = 2 (both sides equal, so you know that 6 is right)

Everyone else seems to say 9 is the answer, but they forgot the key word was "quantity". They simply multiplied 2/3 times x, when in reality you have to multipy 2/3 times x AND 2/3 times negative 3

2006-09-14 14:59:40 · answer #2 · answered by Dave 1 · 0 0

x=9
(2/3)*9 -3 = 6-3 =3

2006-09-13 22:46:38 · answer #3 · answered by DarwinV 2 · 0 0

7/2

2006-09-13 22:40:41 · answer #4 · answered by Donut Head 1 · 0 0

2/3x-3=1/3x subtract 2/3x from each side.
-3=(-1/3x) divide each side by 1/3
-9=-x multply by -1 for make x positive
x=9?

2006-09-13 22:46:01 · answer #5 · answered by Rvardell 3 · 0 0

x = 9.

2/3x = 6

6 - 3 = 3

3 = 1/3 * 9

Thats one solution. I don't think there can be any others.

2006-09-13 22:49:53 · answer #6 · answered by chocolahoma 7 · 0 0

2/3x-3=1/3x
2/3x-1/3x=3
1/3x=3
x=9

2006-09-13 22:41:32 · answer #7 · answered by Anonymous · 0 0

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