Consider the quadratic equation y=5x^2+100x+15 Complete the square to express the quadratic in standard form y=a(x-h)^2+k
a=
h=
k=
Thanks in advance for your help, im stuck!
2006-09-13 15:13:36 · 4 answers · asked by linfinity27 2 in Education & Reference ➔ Homework Help
Ok, the form of the equation is
y=a(x-h)^2 + k
equation is 5x^2+100x +15
5 is a common factor
5(x^2+20x+3)
completing the square
5[(x+10)(x+10)] +15 -100
5[(x+10)]^2 - 85
a= 5
h=-10
k=-85
Good luck.
2006-09-13 15:22:20 · answer #1 · answered by alrivera_1 4 · 0⤊ 0⤋
Move the 15 to the other side
5x^2 + 100x = -15
divide by 5
x^2 + 20x = -3
now add something to both sides to make it normal like 100
x^2 + 20x + 100 = -3 +100
then solve
(x + 10)^2 = 97
square root of both sides
x + 10 = square root(97)
solve for x
x = square root (97) - 10
yay!
2006-09-13 22:26:40 · answer #2 · answered by soccercake7 2 · 0⤊ 0⤋
5(x+10)^2+485
a=5
h=-10
k=485
i think
2006-09-13 22:22:11 · answer #3 · answered by afireinsideme [DF] 6 · 0⤊ 0⤋
This page will answer your problem http://www.1728.com/quadratc.htm
2006-09-13 22:21:06 · answer #4 · answered by D K 3 · 0⤊ 0⤋