What is the time needed for a force of 1340 Newtons to stop the car?
2006-09-13 15:12:36 · 2 answers · asked by Mondai W 1 in Science & Mathematics ➔ Other - Science
I didn't like the other answer. Not saying it's wrong just not the way I'd do it.
F = m*a
F = 1340 Newtons = 1340 Kg *meters/sec^2
m = 12000 kg
a = or in this case deceleration = 1340/12000 = 0.112 meters/sec^2
Velocity = Velocity at t = 0 +a*t Want to know when velocity = 0
0 = 1.7 - a*t a = 0.112
t = 1.7/0.112 = 15.2 sec maybe the first guy was on to something.
2006-09-13 15:29:04 · answer #1 · answered by Roadkill 6 · 0⤊ 0⤋
First find the momentum, 12000 x 1.7. This will be equal to the impulse required to stop the car, impulse is force times time. so the equation is 20400 = 1340(t). t is 15.2 seconds.
2006-09-13 22:15:42 · answer #2 · answered by metropolispt314 2 · 0⤊ 0⤋