Earth-sun distance (avg) 1.496x10^11
2006-09-13 14:37:55 · 3 answers · asked by cheertee1126 1 in Science & Mathematics ➔ Physics
This will have everything to do with units. Your earth-sun avg. distance (radius) is 1.496 E11 km, so the circumference of the ecliptic circle (assuming a circle, not an ellipse) is 4.6998 E11 km, which rounds to 4.700 E11 km.
A year is 365.25 days, which is 8766 hours.
So the speed is 4.700 E11 / 8.766 E3 = 5.36 E7 km/hr
or 53,600,000 km/hr.
2006-09-13 16:14:21 · answer #1 · answered by bpiguy 7 · 1⤊ 0⤋
That sounds like a fun one.
What do we know?
1) the radius distance involved (you gave it),
2) the fact that the Earth goes around the Sun once a year.
3) Pi = 3.14159
That should be all you need!
2006-09-13 14:48:02 · answer #2 · answered by diamondspider 3 · 0⤊ 1⤋
you have to use this equation sqrt of GM/R where G= 6.67x10^-11 and M= 2x10^30 which is the sun's mass and R=149600000000 m which is the distance between the sun and the earth.
2006-09-13 16:01:09 · answer #3 · answered by Anonymous · 0⤊ 1⤋