can someone please help me with this maths equation?

Question

the question is to write this equation in its simplest form.
3n+1+3n / 3n – 3n+1

it would be great if you could show the working out cause then ill understand it more

what do you mean by parent thesis?

3^(n+1)+3^(n) / 3^(n) – 3^(n+1)

sorry i just realised the computer couldnt do to the power of

Answer 1

I'm assuming that everything to the left of the division bar is the numerator, and everything to the right is the denominator. With this in mind, the answer would be -2.

[3^(n+1)+3^n]/[3^n-3^(n+1)] = [(3*3^n)+3^n]/[3^n-(3*3^n)]
=[(3+1)*(3^n)]/[(1-3)*(3^n)]
=[4*(3^n)]/[-2*(3^n)]
=4/-2
=-2

Answer 2

6n+1, 3n-3n is 0 so the denominator is 1.

Answer 3

The answer is 6n+1. The numerator = 6n+1 and the denominator = 1. Therefore, 6n+1/1=6n+1.

Answer 4

Your problem should read

(3^(n+1)+3^n) / (3^n -3^(n+1))

Factor 3^n out of the numerator and denominator gives

3^n(3+1) / 3^n(1-3) = (3+1)/(1-3) = 4/-2 = -2

Make sure you include the parentheses (brackets) in the proper places. The order of priority of operations is PEMDAS:- Parantheses, Exponents, Multiplication, Division, Addition, Subtraction.

Here's a link to help you understand how to present problems and to solve them yourself.

http://www.purplemath.com/modules/orderops.htm

Answer 5

3n+1+3n / 3n – 3n+1
3n+1 + 1 - 3n+1 [do 3n/3n]
3n+3-3n [combine the digits first (1+1+1)]
3 [combined the like terms [3n-3n]

Answer 6

Please clarify using parenthesis.

Is it (3n + 1 + (3n/3n) -3n + 1)?
Or (3n + 1 + 3n)/(3n -3n + 1)?
Or something else?

Answer 7

6n +1 if there are no parentheses'

Answer 8

6n+1


do you know how to use the cancellation method? it's easier
if you know that.