2006-09-13 13:52:20 · 7 answers · asked by cheertee1126 1 in Science & Mathematics ➔ Physics
Earth-Sun distance is 1.496 x 10^11 somehow that is apart of the solution. I am not understand how to get to the answer... mostly the steps involved.
2006-09-13 14:34:36 · update #1
The velocity is 0 because the displacement is 0. Velocity is speed and direction, so because it goes in a circle the velocity would be 0.
2006-09-13 14:01:08 · answer #1 · answered by nighthawk8713 3 · 0⤊ 1⤋
ACTUALLY, you could give the correct answer without any calculation whatsoever... and probably baffle your phsysics teacher that you came up with this. The velocity of the earth over one year is simply 1.
why? because orbital velocity is not measured in m/s but rather in number of orbits per unit time... okay, i take it back because SI units have to be in time values... calculating the number of seconds in a year and then dividing one by that:
1/(365.25 * 24 * 60 * 60) = 3.1688 * 10 ^ -8
there, so the orbital velocity of the earth is 3.1688 * 10 ^ -8 over one second, or 1 over a year. Calculating the total circumference of the orbit (assuming circular orbit) and then dividing by the number of seconds in a year will give you the TANGENTIAL velocity (which is not zero) but who wants to waste the time doing that, or even bother using the tangential velocity in practicality.
2006-09-13 21:41:13 · answer #2 · answered by promethius9594 6 · 0⤊ 0⤋
Figure out how far it goes in a year. We know the distance to the sun (93 million miles, I think, better look it up) then realize that is the radius of the circle. So knowing that, you multiply it by 2 PI and there's you distance. So it's that distance per year.
2006-09-13 13:56:15 · answer #3 · answered by All hat 7 · 0⤊ 0⤋
It travels in more or less of a circle with radius 93 million miles, so can figure the circumference and convert miles per year into miles per hour. Actually nighthawk has an excellent point.
2006-09-13 14:03:59 · answer #4 · answered by banjuja58 4 · 0⤊ 0⤋
Problem is, the orbit is not circular. It's ecliptical. Not sure the exact maths but the distance is well reported in many encyclopedias.
2006-09-13 14:01:23 · answer #5 · answered by donkeyspuzz 1 · 0⤊ 0⤋
circumference of the earth's orbit divided by one year. Convert to m/s.
2006-09-13 13:55:20 · answer #6 · answered by Glenn N 5 · 0⤊ 0⤋
Try this website:
http://helios.gsfc.nasa.gov/qa_earth.html#earthrotn
Hope it helps
2006-09-13 14:28:54 · answer #7 · answered by STRETCH 3 · 0⤊ 0⤋