ALGEBRA O2 Help Please?

Question

although this is algebra 1 review, i cant quite remeber what to do since ive had algebra 1 , two years ago . please help . ive retried the prpblems several times already , and none of seems to make sense. especially numver one , am i suppose to end up with a fraction ?

1 ) 17 - 2y < 5 ( 7 -3y ) - 15


2) 2/3 ( x - 12 ) < x + 8


3) 3/5 ( x - 12 ) > x - 24


4) 3 [ 4x - ( 2x - 7 ) ] < 2( 3x - 5 )

Answer 1

17-2y<5(7-3y)-15 get rid of the parenthases first
17-2y<35-15y-15 now clean up both sides
17-2y<20-15y now move your variable y to one side, what you do to one side you must do to the other.
17-2y<20-15y we will move the -15y so to remove it from the right we must add 15y and we must do it to both sides.
17+13y<20 (see we added 15y + (-2y) to get +13y). now isolate the variable on the left by moving the 17. we must subtract it from both sides
13y<3 now to get the y alone we must divde by 13 so it will cancel out
y< 3/13

#2) Lets start by getting rid of the fraction. (what we do to one side we must do to both)

to get rid of a fraction we multiply all of the factors by the least common denominator, in this case it is 3.
the factors are
2/3(x-12)....x....8 we multipy each of these by 3
2(x-12).....3x...24 so

2(x-12) < 3x + 24 now continue like in the first problem

2x-24<3x+24

-1x-24<24
-1x<48

now here comes the tricky part when you divide by a negative number you must flip your sign
x > -48

the third one you should be able to do now

the fourth one I will help you simplify

start by getting rid of the parantasies, start in the inner ones then work out

3[4x - 2x + 7] < 6x - 10 see how we brought the negative sign into the first set, now lets finish by bringing in the 3

12x - 6x +21 < 6X - 10 Now just simplify this and solve.

good luck

Answer 2

you would possibly want to be high quality. you would possibly want to be in a position to artwork with distinct-variable equations and remedy quadratics (in case you even get to pH on your first semester of chem), yet those are coated in straightforward algebra and also you wouldn't have any difficulty.

Answer 3

you should actually end up with an assortment of numbers since the value of x or y is variable and it is not and equation solve for all the possiblities of both x and y hope this helps

Answer 4

yes I ended up with Y is less than or equal to 9 and three sevenths

Answer 5

Here is a site that walks you through exactly how to solve inequalities: http://www.purplemath.com/modules/ineqsolv.htm

Answer 6

yes

Answer 7

1) -4.4
2)-53.3
3)don't know
4)2.6
I think these are the answers. Don't be mad if they aren't.