2006-09-13 12:38:50 · 5 answers · asked by Benjamin Z 1 in Science & Mathematics ➔ Physics
Position function:
y = y0 + v0*t - (1/2)*9.8*t^2
Velocity function (derivative of position function):
y' = v = v0 - 9.8t
ground level means y0 = 0 meters
initial velocity = v0 = 61 m/s
t = 1 s
v = 61 - 9.8*1
=51.2 m/s
2006-09-13 12:50:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Fast enough you don't want to be in the way of it.
You forgot to mention "how fast" the ball would be traveling at a certain height/distance. Its a no brainer that the ball would launch at 61 m/s, given that is the thrust. Be more specific.
In other words you need Thrust, distance, weight in order to come to an accurate conclusion.
2006-09-13 19:54:00 · answer #2 · answered by Victor ious 6 · 0⤊ 0⤋
61 m/s - 9.8 m/s/s (1 s)=51.2 m/s
2006-09-13 19:44:11 · answer #3 · answered by Glenn N 5 · 0⤊ 0⤋
depends on mass and gravity. Is it in a vacuum, etc?
2006-09-13 19:47:40 · answer #4 · answered by cyanne2ak 7 · 0⤊ 0⤋
61m/s
2006-09-13 19:48:11 · answer #5 · answered by cuutgrl66 2 · 0⤊ 0⤋